File:Surfaces of Mars and Venus (4089158361).jpg
.jpg){kind=small}
Size of this preview: 478 × 599 pixels. Other resolutions: 191 × 240 pixels | 383 × 480 pixels | 612 × 768 pixels | 816 × 1,024 pixels | 2,185 × 2,740 pixels.
Original file (2,185 × 2,740 pixels, file size: 2.81 MB, MIME type: image/jpeg)
 | This is a file from the Wikimedia Commons. Information from its description page there is shown below. Commons is a freely licensed media file repository. You can help. |
Summary
| Description | This comparison shows panoramic views of the surface of Mars from the American Viking spacecraft and the surface of Venus from the Soviet Venera spacecraft. Prepared for NASA by Stephen Paul Meszaros. | ||
| Date | |||
| Source | Surfaces of Mars and Venus | ||
| Author | Lunar and Planetary Institute from Houston, TX, USA | ||
| Other versions |
|
Licensing
This file is licensed under the Creative Commons Attribution 2.0 Generic license.
- You are free:
- to share – to copy, distribute and transmit the work
- to remix – to adapt the work
- Under the following conditions:
- attribution – You must give appropriate credit, provide a link to the license, and indicate if changes were made. You may do so in any reasonable manner, but not in any way that suggests the licensor endorses you or your use.
|
This image was originally posted to Flickr by Lunar and Planetary Institute at https://flickr.com/photos/44301452@N05/4089158361. It was reviewed on 14 January 2021 by FlickreviewR 2 and was confirmed to be licensed under the terms of the cc-by-2.0. |
File history
Click on a date/time to view the file as it appeared at that time.
| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 20:28, 14 January 2021 | | 2,185 × 2,740 (2.81 MB) | Dbigwood | Transferred from Flickr via #flickr2commons |
File usage
No pages on the English Wikipedia use this file (pages on other projects are not listed).
Global file usage
The following other wikis use this file:
- Usage on fa.wikipedia.org
.jpg){kind=link}