Levitzky's theorem

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In mathematics, more specifically ring theory and the theory of nil ideals, Levitzky's theorem, named after Jacob Levitzki, states that in a right Noetherian ring, every nil one-sided ideal is necessarily nilpotent.[1][2] Levitzky's theorem is one of the many results suggesting the veracity of the Köthe conjecture, and indeed provided a solution to one of Köthe's questions as described in (Levitzki 1945). The result was originally submitted in 1939 as (Levitzki 1950), and a particularly simple proof was given in (Utumi 1963).

Proof[edit]

This is Utumi's argument as it appears in (Lam 2001, p. 164-165)

Lemma[3]

Assume that R satisfies the ascending chain condition on annihilators of the form where a is in R. Then

  1. Any nil one-sided ideal is contained in the lower nil radical Nil*(R);
  2. Every nonzero nil right ideal contains a nonzero nilpotent right ideal.
  3. Every nonzero nil left ideal contains a nonzero nilpotent left ideal.
Levitzki's Theorem [4]

Let R be a right Noetherian ring. Then every nil one-sided ideal of R is nilpotent. In this case, the upper and lower nilradicals are equal, and moreover this ideal is the largest nilpotent ideal among nilpotent right ideals and among nilpotent left ideals.

Proof: In view of the previous lemma, it is sufficient to show that the lower nilradical of R is nilpotent. Because R is right Noetherian, a maximal nilpotent ideal N exists. By maximality of N, the quotient ring R/N has no nonzero nilpotent ideals, so R/N is a semiprime ring. As a result, N contains the lower nilradical of R. Since the lower nilradical contains all nilpotent ideals, it also contains N, and so N is equal to the lower nilradical. Q.E.D.

See also[edit]

Notes[edit]

  1. ^ Herstein 1968, p. 37, Theorem 1.4.5
  2. ^ Isaacs 1993, p. 210, Theorem 14.38
  3. ^ Lam 2001, Lemma 10.29.
  4. ^ Lam 2001, Theorem 10.30.

References[edit]