# Derivative test

(Redirected from Second derivative test)

In calculus, a derivative test uses the derivatives of a function to locate the critical points of a function and determine whether each point is a local maximum, a local minimum, or a saddle point. Derivative tests can also give information about the concavity of a function.

The usefulness of derivatives to find extrema is proved mathematically by Fermat's theorem of stationary points.

## First derivative test

The first derivative test examines a function's monotonic properties (where the function is increasing or decreasing) focusing on a particular point in its domain. If the function "switches" from increasing to decreasing at the point, then the function will achieve a highest value at that point. Similarly, if the function "switches" from decreasing to increasing at the point, then it will achieve a least value at that point. If the function fails to "switch", and remains increasing or remains decreasing, then no highest or least value is achieved.

You can examine a function's monotonicity without calculus. However, calculus is usually helpful because there are sufficient conditions that guarantee the monotonicity properties above, and these conditions apply to the vast majority of functions one would encounter.

### Precise statement of monotonicity properties

Stated precisely, suppose f is a real-valued function of a real variable, defined on some interval containing the point x.

• If there exists a positive number r such that f is increasing on (xr, x) and decreasing on (x, x + r), then f has a local maximum at x.
• If there exists a positive number r such that f is decreasing on (xr, x) and increasing on (x, x + r), then f has a local minimum at x.
• If there exists a positive number r such that f is strictly increasing on (xr, x] and strictly increasing on [x, x + r), then f is strictly increasing on (xr, x + r) and does not have a local maximum or minimum at x.
• If there exists a positive number r such that f is strictly decreasing on (xr, x] and strictly decreasing on [x, x + r), then f is strictly decreasing on (xr, x + r) and does not have a local maximum or minimum at x.

Note that in all the two cases, f is required to be strictly increasing or strictly decreasing to the left or right of x, while in the last two cases, f is required to be strictly increasing or strictly decreasing. The reason is that in the definition of local maximum and minimum, the inequality is required to be strict: e.g. No value of a constant function is either a local maximum or a local minimum.

### Precise statement of first derivative test

The first derivative test depends on the "increasing-decreasing test", which is itself ultimately a consequence of the mean value theorem.

Suppose f is a real-valued function of a real variable defined on some interval containing the critical point a. Further suppose that f is continuous at a and differentiable on some open interval containing a, except possibly at a itself.

• If there exists a positive number r such that for every x in (a - r, a] we have f'(x) ≥ 0, and for every x in [a, a + r) we have f'(x) ≤ 0, then f has a local maximum at a.
• If there exists a positive number r such that for every x in (a - r, a) we have f'(x) ≤ 0, and for every x in (a, a + r) we have f'(x) ≥ 0, then f has a local minimum at a.
• If there exists a positive number r such that for every x in (a - r, a) (a, a + r) we have f'(x) > 0, or if there exists a positive number r such that for every x in (a - r, a) (a, a + r) we have f'(x) < 0, then f has neither a local maximum nor a local minimum at a.
• If none of the above conditions hold, then the test fails. (Such a condition is not vacuous; there are functions that satisfy none of the first three conditions.)

Again, corresponding to the comments in the section on monotonicity properties, note that in the first two cases, the inequality is not required to be strict, while in the third case, strict inequality is required.

### Applications

The first derivative test is helpful in solving optimization problems in physics, economics, and engineering. In conjunction with the extreme value theorem, it can be used to find the absolute maximum and minimum of a real-valued function defined on a closed, bounded interval. In conjunction with other information such as concavity, inflection points, and asymptotes, it can be used to sketch the graph of a function.

## Second derivative test

After establishing the critical points of a function, the second derivative test uses the value of the second derivative at those points to determine whether such points are a local maximum or a local minimum. If the function f is twice differentiable at a critical point x (i.e. f'(x) = 0), then:

• If $\ f^{\prime\prime}(x) < 0$ then $\ f$ has a local maximum at $\ x$.
• If $\ f^{\prime\prime}(x) > 0$ then $\ f$ has a local minimum at $\ x$.
• If $\ f^{\prime\prime}(x) = 0$, the test is inconclusive.

In the latter case, Taylor's Theorem may be used to determine the behavior of f near x using higher derivatives.

### Multivariable case

For a function of more than one variable, the second derivative test generalizes to a test based on the eigenvalues of the function's Hessian matrix at the critical point. In particular, assuming that all second order partial derivatives of f are continuous on a neighbourhood of a critical point x, then if the eigenvalues of the Hessian at x are all positive, then x is a local minimum. If the eigenvalues are all negative, then x is a local maximum, and if some are positive and some negative, then the point is a saddle point. If the Hessian matrix is singular, then the second derivative test is inconclusive.

### Proof of the second derivative test

Suppose we have $f''(x) > 0$ (the proof for $f''(x) < 0$ is analogous). By assumption, $f'(x) = 0$. Then

$0 < f''(x) = \lim_{h \to 0} \frac{f'(x + h) - f'(x)}{h} = \lim_{h \to 0} \frac{f'(x + h) - 0}{h} = \lim_{h \to 0} \frac{f'(x+h)}{h}.$

Thus, for h sufficiently small we get

$\frac{f'(x+h)}{h} > 0$

which means that $f'(x+h) < 0$ if h < 0 (intuitively, f is decreasing as it approaches x from the left), and that $f'(x+h) > 0$ if h > 0 (intuitively, f is increasing as we go right from x). Now, by the first derivative test, $f$ has a local minimum at $x$.

### Concavity test

A related but distinct use of second derivatives is to determine whether a function is concave up or concave down at a point. It does not, however, provide information about inflection points. Specifically, a twice-differentiable function f is concave up if $\ f''(x) > 0$ and concave down if $\ f''(x) < 0$. Note that if $\ f(x) = x^4$, then $\ x=0$ has zero second derivative, yet is not an inflection point, so the second derivative alone does not give enough information to determine if a given point is an inflection point.

## Higher-order derivative test

The higher-order derivative test or general derivative test is able to determine whether a function's critical points are maxima, minima, or points of inflection for a wider variety of functions than the second-order derivative test. As shown below, the second derivative test is mathematically identical to the special case of n=1 in the general derivative test.

Let $f(x)$ be a real-valued, sufficient differentiable function on the interval $I \subset \R, \; c \in I$ and $n \ge 1$ an integer. Also let all the derivatives of $f(x)$ at $x=c$ be zero up to and including the nth derivative, but the with the (n+1) derivative being non-zero:

$f'(c)=\cdots=f^{(n)}(c)=0\quad \text{and}\quad f^{(n+1)}(c)\,\not= 0$.

There are four possibilities, the first two cases where c is an extremum, the second two where c is a (local) saddle point:

• If n is odd and $f^{(n+1)}(c)<0$, then c is a local maximum.
• If n is odd and $f^{(n+1)}(c)>0$, then c is a local minimum.
• If n is even and $f^{(n+1)}(c)<0$, then c is a strictly decreasing point of inflection.
• If n is even and $f^{(n+1)}(c)>0$, then c is a strictly increasing point of inflection.

n must be either odd or even, so this analytical test classifies any stationary point of $f$.

### Example

Say we want to perform the general derivative test on the function $f(x)=x^6+5$ at the point x=0. To do this, we calculate the derivatives of the function and then evaluate them at the point of interest until the result is nonzero.

$f'(x)=6x^5$, $f'(0)=0$
$f''(x)=30x^4$, $f''(0)=0$
$f^{(3)}(x)=120x^3$, $f^{(3)}(0)=0$
$f^{(4)}(x)=360x^2$, $f^{(4)}(0)=0$
$f^{(5)}(x)=720x$, $f^{(5)}(0)=0$
$f^{(6)}(x)=720$, $f^{(6)}(0)=720$

As shown above, at x=0, the function $x^6+5$ has all of its derivatives at 0 equal to 0 except for the 6th derivative, which is positive. Thus n=5, and by the test, there is a local minimum at 0.