Jump to content

Sokołowo, Golub-Dobrzyń County

Coordinates: 53°05′00″N 19°07′00″E / 53.0833°N 19.1167°E / 53.0833; 19.1167
From Wikipedia, the free encyclopedia

This is an old revision of this page, as edited by Yobot (talk | contribs) at 18:14, 17 September 2013 (→References: WP:CHECKWIKI error fixes / special characters in pagetitle using AWB (9485)). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

For other places with the same name, see Sokołowo.
Sokołowo
Village
Country Poland
VoivodeshipKuyavian-Pomeranian
CountyGolub-Dobrzyń
GminaGmina Golub-Dobrzyń

Sokołowo [sɔkɔˈwɔvɔ] is a village in the administrative district of Gmina Golub-Dobrzyń, within Golub-Dobrzyń County, Kuyavian-Pomeranian Voivodeship, in north-central Poland.[1] It lies approximately 5 kilometres (3 mi) south-east of Golub-Dobrzyń and 34 km (21 mi) east of Toruń.

References

  1. ^ "Central Statistical Office (GUS) – TERYT (National Register of Territorial Land Apportionment Journal)" (in Polish). 2008-06-01.


53°05′00″N 19°07′00″E / 53.0833°N 19.1167°E / 53.0833; 19.1167


Stub icon

This Golub-Dobrzyń County location article is a stub. You can help Wikipedia by expanding it.

Retrieved from "https://en.wikipedia.org/w/index.php?title=Sokołowo,_Golub-Dobrzyń_County&oldid=573368552"