1910 Vermont gubernatorial election
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| Elections in Vermont |
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The Vermont gubernatorial election of 1910 took place on September 6, 1910. Incumbent Republican George H. Prouty, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate John A. Mead defeated Democratic candidate Charles D. Watson to succeed him.
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | John A. Mead | 35,263 | 64.2 | ||
| Democratic | Charles D. Watson | 17,425 | 31.7 | ||
| Prohibition | Edwin R. Towle | 1,044 | 1.9 | ||
| Socialist | Chester E. Ordway | 1,055 | 1.9 | ||
| N/A | Other | 141 | 0.3 | ||
| Total votes | '54,928' | '100' | |||
References
- ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 1 January 2015.
- ^ "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Retrieved 1 January 2015.
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