Bloomfield Township, LaGrange County, Indiana

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Bloomfield Township
Township
Map highlighting Bloomfield Township, LaGrange County, Indiana.svg
Coordinates: 41°38′56″N 85°21′31″W / 41.64889°N 85.35861°W / 41.64889; -85.35861Coordinates: 41°38′56″N 85°21′31″W / 41.64889°N 85.35861°W / 41.64889; -85.35861
Country United States
State Indiana
County LaGrange
Government
 • Type Indiana township
Area
 • Total 35.85 sq mi (92.9 km2)
 • Land 35.58 sq mi (92.2 km2)
 • Water 0.27 sq mi (0.7 km2)
Elevation[1] 945 ft (288 m)
Population (2010)
 • Total 5,412
 • Density 152.1/sq mi (58.7/km2)
FIPS code 18-05752[2]
GNIS feature ID 453113

Bloomfield Township is one of eleven townships in LaGrange County, Indiana. As of the 2010 census, its population was 5,412 and it contained 2,231 housing units.[3]

Bloomfield Township was founded in 1835.[4]

Geography[edit]

According to the 2010 census, the township has a total area of 35.85 square miles (92.9 km2), of which 35.58 square miles (92.2 km2) (or 99.25%) is land and 0.27 square miles (0.70 km2) (or 0.75%) is water.[3]

References[edit]

  1. ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31. 
  2. ^ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31. 
  3. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10. 
  4. ^ Counties of LaGrange and Noble, Indiana: Historical and Biographical. F.A. Battey & Company. 1882. p. 126. 

External links[edit]