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Harlan Township, Fayette County, Iowa

Coordinates: 42°46′51″N 91°54′45″W / 42.78083°N 91.91250°W / 42.78083; -91.91250
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Harlan Township
Township
Location in Fayette County
Location in Fayette County
Coordinates: 42°46′51″N 91°54′45″W / 42.78083°N 91.91250°W / 42.78083; -91.91250
Country United States
State Iowa
CountyFayette
Area
 • Total36.79 sq mi (95.28 km2)
 • Land36.76 sq mi (95.22 km2)
 • Water0.03 sq mi (0.07 km2)  0.07%
Elevation
1,145 ft (349 m)
Population
 (2010)
 • Total871
 • Density24/sq mi (9.1/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
ZIP codes
50655, 50662, 50681, 52142, 52164
GNIS feature ID0468005

Harlan Township is one of twenty townships in Fayette County, Iowa. As of the 2010 census, its population was 871.[1]

Geography

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According to the United States Census Bureau, Harlan Township covers an area of 36.79 square miles (95.28 square kilometers); of this, 36.76 square miles (95.22 square kilometers, 99.94 percent) is land and 0.03 square miles (0.07 square kilometers, 0.07 percent) is water.

Cities, towns, villages

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Adjacent townships

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Cemeteries

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The township contains these two cemeteries: Hope and Long Grove.

Major highways

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Landmarks

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  • City Park
  • Twin Bridges County Park (east quarter)

School districts

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  • West Central Community School District

Political districts

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References

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  1. ^ "Profile of General Population and Housing Characteristics: 2010 Demographic Profile Data (DP-1): Harlan township, Fayette County, Iowa". United States Census Bureau. Retrieved March 5, 2012.
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