1832 United States presidential election in Delaware
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| Elections in Delaware |
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The 1832 United States presidential election in Delaware took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
Delaware voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Delaware by a margin of 0.98%.
Results
| United States presidential election in Delaware, 1832[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| National Republican | Henry Clay | 4,276 | 50.99% | 3 | |
| Democratic | Andrew Jackson | 4,110 | 49.01% | 0 | |
| Totals | 8,386 | 100.0% | 3 | ||
References
- ^ "1832 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 12 April 2013.
State and district results of the 1832 United States presidential election | ||
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