Solenoidal vector field: Difference between revisions
Appearance
Content deleted Content added
No edit summary |
revert layman |
||
Line 15: | Line 15: | ||
'''A''' such that <math>\mathbf{v} = \nabla \times \mathbf{A}</math>. (Strictly, this holds only subject to certain technical conditions on '''v'''.) |
'''A''' such that <math>\mathbf{v} = \nabla \times \mathbf{A}</math>. (Strictly, this holds only subject to certain technical conditions on '''v'''.) |
||
Examples |
==Examples== |
||
* one of [[Maxwell's equations]] states that the [[magnetic field]] '''B''' is solenoidal; |
* one of [[Maxwell's equations]] states that the [[magnetic field]] '''B''' is solenoidal; |
||
* the [[velocity]] field of an [[incompressible fluid flow]] is solenoidal. |
* the [[velocity]] field of an [[incompressible fluid flow]] is solenoidal. |
||
A word of caution: |
|||
This is the "layman's" proof. The del operator (or nabla) cannot be crossed or dotted with any other vector (strictly speaking) because it is not a real vector. It is an imaginary scalar quantity which corresponds to a mathematical operation. |
|||
{{Mathanalysis-stub}} |
{{Mathanalysis-stub}} |
||
⚫ | |||
[[Category:Vector calculus]] |
[[Category:Vector calculus]] |
||
[[Category:Fluid dynamics]] |
[[Category:Fluid dynamics]] |
||
⚫ |
Revision as of 22:20, 13 November 2005
In vector calculus a solenoidal vector field is a vector field v with divergence zero:
This condition is clearly satisfied whenever v has a vector potential, because if
then
The converse holds: for any solenoidal v there exists a vector potential A such that . (Strictly, this holds only subject to certain technical conditions on v.)
Examples
- one of Maxwell's equations states that the magnetic field B is solenoidal;
- the velocity field of an incompressible fluid flow is solenoidal.