Talk:Dirichlet's theorem on arithmetic progressions: Difference between revisions
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: Chowla proved there are infinitely many three consecutive terms in every arithmetic progression. We should also correct this piece of sentence: |
: Chowla proved there are infinitely many three consecutive terms in every arithmetic progression. We should also correct this piece of sentence: |
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:: ''...where n is a...'' --[[User:XJamRastafire|XJamRastafire]] 12:28 Oct 11, 2002 (UTC) |
:: ''...where n is a...'' --[[User:XJamRastafire|XJamRastafire]] 12:28 Oct 11, 2002 (UTC) |
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I think the part |
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<blockquote> |
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Note that the theorem does not say that there are infinitely many consecutive terms in the arithmetic progression |
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a, a+d, a+2d, a+3d, ..., |
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which are prime. |
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</blockquote> |
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Would be easier to read if it said "Note that the theorem does not say that there are infinitely many consecutive prime terms in the arithmetic progression..."--or perhaps better: "...infinitely many consecutive primes...". |
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- Chowla proved this for the case of three consecutive terms.
What exactly did Chowla prove? AxelBoldt 02:20 Oct 10, 2002 (UTC)
- Chowla proved there are infinitely many three consecutive terms in every arithmetic progression. We should also correct this piece of sentence:
- ...where n is a... --XJamRastafire 12:28 Oct 11, 2002 (UTC)
I think the part
Note that the theorem does not say that there are infinitely many consecutive terms in the arithmetic progression
a, a+d, a+2d, a+3d, ..., which are prime.
Would be easier to read if it said "Note that the theorem does not say that there are infinitely many consecutive prime terms in the arithmetic progression..."--or perhaps better: "...infinitely many consecutive primes...".