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==Explanation==
==Explanation==
The name ''vector boson'' arises from [[quantum field theory]]. The [[vector component|component]] of such a particle's spin along any axis has the three [[eigenvalue]]s −''ħ'', 0, and +''ħ'' (where ''ħ'' is the [[reduced Planck constant]]), meaning that any measurement of it can only yield one of these values. (This is, at least, true for [[rest mass|massive]] vector bosons; the situation is a bit different for [[massless particle]]s such as the photon, for reasons beyond the scope of this article. See [[Wigner's classification]].<ref>[[Robert Weingard|Weingard, Robert]]. [http://bjps.oxfordjournals.org/content/40/2/287.full.pdf "Some Comments Regarding Spin and Relativity"]</ref>) The space of spin [[quantum state|states]] therefore is a discrete [[Degrees of freedom (physics and chemistry)|degree of freedom]] consisting of three states, the same as the number of components of a [[Euclidean vector|vector]] in three-dimensional space. [[Quantum superposition]]s of these states can be taken such that they transform under [[rotation formalisms in three dimensions|rotations]] just like the spatial components of a rotating vector{{Citation needed|date=September 2011}} (the so named [[representation theory of SU(2)|'''3''' representation of SU(2)]]). If the vector boson is taken to be the [[quantum]] of a field, the field is a [[vector field]], hence the name.
The name ''vector boson'' arises from [[quantum field theory]]. The [[vector component|component]] of such a particle's spin along any axis has the three [[eigenvalue]]s −''ħ'', 0, and +''ħ'' (where ''ħ'' is the [[reduced Planck constant]]), meaning that any measurement of its spin can only yield one of these values. (This is, at least, true for [[rest mass|massive]] vector bosons; the situation is a bit different for [[massless particle]]s such as the photon, for reasons beyond the scope of this article. See [[Wigner's classification]].<ref>[[Robert Weingard|Weingard, Robert]]. [http://bjps.oxfordjournals.org/content/40/2/287.full.pdf "Some Comments Regarding Spin and Relativity"]</ref>) The space of spin [[quantum state|states]] therefore is a discrete [[Degrees of freedom (physics and chemistry)|degree of freedom]] consisting of three states, the same as the number of components of a [[Euclidean vector|vector]] in three-dimensional space. [[Quantum superposition]]s of these states can be taken such that they transform under [[rotation formalisms in three dimensions|rotations]] just like the spatial components of a rotating vector{{Citation needed|date=September 2011}} (the so named [[representation theory of SU(2)|'''3''' representation of SU(2)]]). If the vector boson is taken to be the [[quantum]] of a field, the field is a [[vector field]], hence the name.


==See also==
==See also==

Revision as of 15:23, 4 April 2017

In particle physics, a vector boson is a boson with the spin equal to 1. The vector bosons regarded as elementary particles in the Standard Model are the gauge bosons, which are the force carriers of fundamental interactions: the photon of electromagnetism, the W and Z bosons of the weak interaction, and the gluons of the strong interaction. Some composite particles are vector bosons, for instance any vector meson (quark and antiquark). During the 1970s and 1980s, intermediate vector bosons—vector bosons of "intermediate"[clarification needed] mass—drew much attention in particle physics.[citation needed]

Vector bosons and the Higgs

The Z and W particles interact with the recently confirmed (March 14, 2013)[1] Higgs Boson, as shown by the attached Feynman diagram.

Feynman diagram of the fusion of two electroweak vector bosons to the scalar Higgs boson, which is a prominent process of the generation of Higgs bosons at particle accelerators.
(The symbol q means a quark particle, W and Z are the vector bosons of the electroweak interaction. H0 is the Higgs boson.)

Explanation

The name vector boson arises from quantum field theory. The component of such a particle's spin along any axis has the three eigenvaluesħ, 0, and +ħ (where ħ is the reduced Planck constant), meaning that any measurement of its spin can only yield one of these values. (This is, at least, true for massive vector bosons; the situation is a bit different for massless particles such as the photon, for reasons beyond the scope of this article. See Wigner's classification.[2]) The space of spin states therefore is a discrete degree of freedom consisting of three states, the same as the number of components of a vector in three-dimensional space. Quantum superpositions of these states can be taken such that they transform under rotations just like the spatial components of a rotating vector[citation needed] (the so named 3 representation of SU(2)). If the vector boson is taken to be the quantum of a field, the field is a vector field, hence the name.

See also

Notes