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Physics of firearms

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From the viewpoint of physics (dynamics, to be exact), a firearm, as for most weapons, is a system for delivering maximum destructive energy to the target with minimum delivery of energy on the shooter. The momentum delivered to the target however cannot be any more than that (due to recoil) on the shooter. This is because the momentum imparted to the bullet is equal to that imparted to the gun-shooter system.

Firearm energy efficiency

From a thermodynamical point of view is firearm special type of piston engine, or in general heat enegine where the bullet has a function of piston. The Energy conversion efficiency of firearm strongly depends on its construction, especially on caliber and barrel lenght. However for illustration there is energy bilance of typical small firearm for .300 Hawk ammunition [1] :

  • Projectile motion 32%
  • Barrel friction 2%
  • Hot gases 34%
  • Barrel heat 30%
  • Unburned propellant 1%.

which is comperable with typical piston engine.

Higher efficiency could be achived in longer barrel firearms because better volume ratio. However, the efficiency gain is less than corresponding to the volume ratio, because the expansion is not trully adiabatic and burnt gas become cold faster because of exchange of heat with the barrel. Large firearm (such as cannon) achieve smaller barrel-heating loss, because better volume-to-surface ratio. High diameter of barrel is also helpful because of lower barrel friction induced by sealing compared to accelerating force. The force is proportional to the square of barrel diameter while sealing needs are proportional to the perimeter by the same pressure.

Force

Assuming the gun and shooter are at rest, the force on the bullet is equal to that on the gun-shooter. This is due to Newton's third law of motion (For every action, there is an equal and opposite reaction). Consider a system where the gun and shooter have a combined mass M and the bullet has a mass m. When the gun is fired, the two systems move away from one another with new velocities V and v respectively. But the law of conservation of momentum states that the magnitudes of their momenta must be equal:

Since force equals the rate of change in momentum and the initial momenta are zero, the force on the bullet must therefore be the same as the force on the gun/shooter.

Hollywood depictions of firearm victims being thrown through plate-glass windows are inaccurate. Were this to be the case, the shooter would also be thrown backwards with equal force. Gunshot victims frequently fall or collapse when shot; this is less a result of the momentum of the bullet pushing them over, but is primarily caused by physical damage or psychological effects, perhaps combined with being off-balance. This is not the case if the victim is hit by heavier projectiles such as 20 mm cannon shell, where the momentum effects can be enormous; this is why very few such weapons can be fired without being mounted on a weapons platform or involve a recoilless system (e.g. a recoilless rifle).

Velocity

From Eq. 1 we can write for the velocity of the gun/shooter: V = mv/M. This shows that despite the high velocity of the bullet, the small bullet-mass to shooter-mass ratio results in a low recoil velocity (V) although the force and momentum are equal.

Kinetic Energy

However, the smaller mass of the bullet, compared that of the gun-shooter system, allows significantly more kinetic energy to be imparted to the bullet than to the shooter. The kinetic energy for the two systems are for the gun-shooter system and for the bullet. The energy imparted to the shooter can then be written as:

If we now write for the ratio of these energies we have:

The ratio of the kinetic energies is the same as the ratio of the masses (and is independent of velocity). Since the mass of the bullet is much less than that of the shooter there is more kinetic energy transferred to the bullet than to the shooter. Once discharged from the weapon, the bullet's energy decays throughout its flight, until the remainder is dissipated by colliding with a target (e.g. deforming the bullet and target).

Transfer of Energy

When the bullet strikes, its high velocity and small frontal cross-section means that it will exert large stresses in any object it hits. This usually results in it penetrating any soft object, such as flesh. The energy is then dissipated in the wound track formed by the passage of the bullet. See terminal ballistics for a fuller discussion of these effects.

Bulletproof vests work by dissipating the bullet's energy in another way; the vest's material, usually Aramid (Kevlar or Twaron), works by presenting a series of material layers which catch the bullet and spread its imparted force over a larger area, hopefully bringing the round to a stop before it can penetrate into the body. While the vest can prevent a bullet from penetrating, the wearer will still be affected by the kinetic energy of the bullet, which can produce serious internal injuries.

Bullets in water

The television show MythBusters undertook to study the behavior of projectiles fired into water; comparing several firearms including a muzzle-loader, a Beretta 9mm semi-automatic pistol, a .357 magnum, an M1 Garand, a .50 caliber rifle, and a shotgun with a deer slug, they found that the lower velocity projectiles had lethal penetration at a distance of 8-10 feet, while high velocity projectiles fragmented upon contact with the water.[2][3]

They followed this with an experiment on firing guns underwater, using a Beretta 9mm semi-automatic pistol, a .357 magnum, an M1 Garand, and a shotgun. While all the guns successfully fired underwater, the shotgun was completely destroyed, with the barrel splitting. The bullets were unable to provide lethal penetration after traveling two feet (approximately 0.6 meters).

See also

References