Talk:Jordan's lemma

Mathematics Stub‑class Low‑priority

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Isn't there a restriction on the power of Jordan's Lemma? Something like, g(r) must go to 0 as fast or faster than 1/R? There's a slightly weaker theorem like 1/R^2, and then Jordan's covers all your bases. Can't find it on the web, and I don't see it here...

You don't need it 203.200.95.130 20:20, 26 August 2007 (UTC)[reply]

Error near top?

g(z)=\frac{1}{1+z^2} is a valid function for Jordan's Lemma, but g(z)=\frac{1}{z} is not.

Surely that's only for the case a=0?

I'm not sure that we should even include this case, as the references don't seem to include it as part of Jordan's lemma.

--Ryanl (talk) 10:47, 14 April 2008 (UTC)[reply]

final limit in proof

Shouldn't this limit equal pi/a rather than 0?