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1966 United States Senate election in Rhode Island

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1966 United States Senate election in Rhode Island

← 1960 November 8, 1966 1972 →
 
Nominee Claiborne Pell Ruth M. Briggs
Party Democratic Republican
Popular vote 219,331 104,838
Percentage 67.66% 32.34%

Pell:      50–60%      60–70%      70–80%      80–90%
Briggs:      50–60%

U.S. senator before election

Claiborne Pell
Democratic

Elected U.S. Senator

Claiborne Pell
Democratic

The 1966 United States Senate election in Rhode Island took place on November 8, 1966. Incumbent Democratic U.S. Senator Claiborne Pell successfully sought re-election, defeating Republican Ruth M. Briggs with 67.66% of the vote.

Primary elections

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Primary elections were held on September 13, 1966.

Democratic primary

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Candidates

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Results

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Democratic primary results[1][2]
Party Candidate Votes %
Democratic Claiborne Pell (Incumbent) unopposed

Republican primary

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Candidates

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Results

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Republican primary results[1][2]
Party Candidate Votes %
Republican Ruth M. Briggs 15,451 82.13%
Republican Charles H. Eden 3,363 17.87%
Total votes 18,814 100.00%

General election

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Results

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General election results [4][5][6][7]
Party Candidate Votes %
Democratic Claiborne Pell (Incumbent) 219,331 67.66
Republican Ruth M. Briggs 104,838 32.34
Majority 114,493 35.32
Turnout 324,169
Democratic hold

References

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  1. ^ a b Congressional Quarterly 1998, p. 150.
  2. ^ a b America Votes 7, p. 372.
  3. ^ "Rhode Island". Des Moines Tribune. Des Moines, Iowa. September 14, 1966. p. 3. Retrieved July 3, 2021.
  4. ^ Clerk of the U.S. House of Representatives (1967). "Statistics of the Presidential and Congressional Election of November 8, 1966" (PDF). U.S. Government Printing Office.
  5. ^ "RI US Senate, 1966". OurCampaigns. Retrieved July 3, 2021.
  6. ^ Congressional Quarterly 1998, p. 96.
  7. ^ America Votes 7, p. 352.

Bibliography

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