Jump to content

1998 Paegas Czech Open

From Wikipedia, the free encyclopedia
(Redirected from 1998 Prague Open)
1998 Paegas Czech Open
Date27 April – 3 May
Edition12th
CategoryWorld Series
Draw32S / 16D
Prize money$340,000
SurfaceClay / outdoor
LocationPrague, Czech Republic
VenueI. Czech Lawn Tennis Club
Champions
Singles
Brazil Fernando Meligeni[1]
Doubles
Australia Wayne Arthurs / Australia Andrew Kratzmann[2]
← 1997 · Prague Open · 1999 →

The 1998 Paegas Czech Open, also known as the Prague Open, was a men's tennis tournament played on outdoor clay courts in Prague, Czech Republic that was part of the World Series of the 1998 ATP Tour. It was the twelfth edition of the tournament and was held from 27 April until 3 May 1998. Unseeded Fernando Meligeni won the singles title.[3]

Finals

[edit]

Singles

[edit]

Brazil Fernando Meligeni defeated Czech Republic Ctislav Doseděl, 6–1, 6–4.

  • It was Meligeni's 1st singles title of the year and the 3rd and last of his career.

Doubles

[edit]

Australia Wayne Arthurs / Australia Andrew Kratzmann defeated Sweden Fredrik Bergh / Sweden Nicklas Kulti, 6–1, 6–1.

See also

[edit]

References

[edit]
  1. ^ "1998 Prague – Singles draw". Association of Tennis Professionals (ATP).
  2. ^ "1998 Prague – Doubles draw". Association of Tennis Professionals (ATP).
  3. ^ John Barrett, ed. (1999). International Tennis Federation World of Tennis 1999. London: CollinsWillow. p. 158. ISBN 9780002188623.
[edit]