1832 United States presidential election in Delaware

Main article: 1832 United States presidential election

1832 United States presidential election in Delaware

November 2 – December 5, 1832

Nominee Henry Clay Andrew Jackson Party National Republican Democratic Home state Kentucky Tennessee Running mate John Sergeant Martin Van Buren Electoral vote 3 0 Popular vote 4,276 4,110 Percentage 50.99% 49.01%

The 1832 United States presidential election in Delaware took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won the state by a narrow margin of 0.98%. This was the first election in which Delaware voted by popular vote for President.

Results

1832 United States presidential election in Delaware
Party		Candidate	Votes	Percentage	Electoral votes
	National Republican	Henry Clay	4,276	50.99%	3
	Democratic	Andrew Jackson	4,110	49.01%	0
Totals			8,386	100.00%	3

See also

• United States presidential elections in Delaware