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David Island

Coordinates: 66°25′S 98°46′E / 66.417°S 98.767°E / -66.417; 98.767
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This is the current revision of this page, as edited by Scottyoak2 (talk | contribs) at 20:41, 27 December 2022 (Adding short description: "Island in Queen Mary Land, Antarctica"). The present address (URL) is a permanent link to this version.

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Not to be confused with Davids Island (New York), Davids Island (Nunavut), or Davis Island (disambiguation).

David Island (66°25′S 98°46′E / 66.417°S 98.767°E / -66.417; 98.767) is an ice-covered island, 10 miles (16 km) long and 6 miles (10 km) wide, marked by rock exposures along its north and east sides, lying off Davis Peninsula in the Shackleton Ice Shelf in Antarctica. It was discovered in November 1912 by the Western Base party of the Australasian Antarctic Expedition (AAE) under Douglas Mawson. Mawson named the island for Edgeworth David, a member of the AAE Advisory Committee.

See also

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References

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  • Public Domain This article incorporates public domain material from "David Island". Geographic Names Information System. United States Geological Survey.


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