Jump to content

Łopuchowo, Sejny County

Coordinates: 54°6′N 23°18′E / 54.100°N 23.300°E / 54.100; 23.300
From Wikipedia, the free encyclopedia

This is the current revision of this page, as edited by Kiwipete (talk | contribs) at 21:25, 16 September 2023 (Format administrative division links, remove DEFAULTSORTKEY as per WP:SORTKEY, remove One Source for stubs, minor formatting changes (AWB)). The present address (URL) is a permanent link to this version.

(diff) ← Previous revision | Latest revision (diff) | Newer revision → (diff)
Łopuchowo
Village
Łopuchowo is located in Poland
Łopuchowo
Łopuchowo
Coordinates: 54°6′N 23°18′E / 54.100°N 23.300°E / 54.100; 23.300
Country Poland
VoivodeshipPodlaskie
CountySejny
GminaKrasnopol

Łopuchowo [wɔpuˈxɔvɔ], is a village in the administrative district of Gmina Krasnopol, within Sejny County, Podlaskie Voivodeship, in north-eastern Poland.[1] It lies approximately 7 kilometres (4 mi) east of Krasnopol, 5 km (3 mi) south-west of Sejny, and 110 km (68 mi) north of the regional capital Białystok.

References

[edit]
  1. ^ "Central Statistical Office (GUS) – TERYT (National Register of Territorial Land Apportionment Journal)" (in Polish). 2008-06-01.