Jump to content

Fleurus Island

Coordinates: 64°34′S 62°13′W / 64.567°S 62.217°W / -64.567; -62.217
From Wikipedia, the free encyclopedia

This is an old revision of this page, as edited by FreeToDisagree (talk | contribs) at 23:05, 31 October 2019 (Removed the orphan-tag since the article is no longer an orphan.). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

Fleurus Island (64°34′S 62°13′W / 64.567°S 62.217°W / -64.567; -62.217) is an island lying 0.5 nautical miles (1 km) south of Delaite Island in Wilhelmina Bay, off the west coast of Graham Land, Antarctica. it was shown on an Argentine government chart of 1950, and was named by the UK Antarctic Place-Names Committee in 1956 after the British ship Fleurus, which visited the area in 1928.[1]

See also

References

  1. ^ "Fleurus Island". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 2012-03-27.

Public Domain This article incorporates public domain material from "Fleurus Island". Geographic Names Information System. United States Geological Survey.


Stub icon

This Danco Coast location article is a stub. You can help Wikipedia by expanding it.

Retrieved from "https://en.wikipedia.org/w/index.php?title=Fleurus_Island&oldid=923970566"