1860 United States presidential election in Connecticut
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| Elections in Connecticut |
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The 1860 United States presidential election in Connecticut took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose 6 electors of the Electoral College, who voted for president and vice president.
Connecticut was won by Republican candidate Abraham Lincoln, who won by a margin of 32.36%.
Results
| 1860 United States presidential election in Connecticut[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 43,486 | 53.86% | 6 | 100.00% | ||
| Democratic | Stephen A. Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 17,364 | 21.50% | 0 | 0.00% | ||
| Southern Democratic | John C. Breckinridge of Kentucky | Joseph Lane of Oregon | 16,558 | 20.51% | 0 | 0.00% | ||
| Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 3,337 | 4.13% | 0 | 0.00% | ||
| Total | 80,745 | 100.00% | 6 | 100.00% | ||||
References
- ^ "1860 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved 24 December 2013.
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