Douglas Township, Saunders County, Nebraska
Appearance
Douglas Township | |
---|---|
![]() Location in Saunders County | |
Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W | |
Country | United States |
State | Nebraska |
County | Saunders |
Area | |
• Total | 32.01 sq mi (82.91 km2) |
• Land | 32.01 sq mi (82.91 km2) |
• Water | 0 sq mi (0 km2) 0% |
Elevation | 1,309 ft (399 m) |
Population (2000) | |
• Total | 196 |
• Density | 6.1/sq mi (2.4/km2) |
GNIS feature ID | 0837967 |
Douglas Township is one of twenty-four townships in Saunders County, Nebraska, United States. The population was 196 at the 2000 census. A 2006 estimate placed the township's population at 205.[1]
See also
References
- ^ "Subcounty population estimates: Nebraska 2000-2006". United States Census Bureau, Population Division. 2007-06-28. Archived from the original (CSV) on 2008-02-18. Retrieved 2008-03-04.
External links