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1978 WCT Tournament of Champions – Singles

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Singles
1978 WCT Tournament of Champions
Final
ChampionSweden Björn Borg
Runner-upUnited States Vitas Gerulaitis
Score6–5, 5–6, 6–4, 6–5
← 1977 · WCT Tournament of Champions · 1979 →

Harold Solomon was the defending champion, but lost in semifinals to Vitas Gerulaitis.[1]

Björn Borg won the title by defeating Vitas Gerulaitis 6–5, 5–6, 6–4, 6–5 in the final.[2]

Seeds

  1. United States Jimmy Connors (First round)
  2. Sweden Björn Borg (Champion)
  3. United States Vitas Gerulaitis (Final)
  4. United States Eddie Dibbs (Quarterfinals)

Draw

First Round Quarterfinals Semifinals Final
1 United States Jimmy Connors 3 0
United States Jeff Borowiak 6 6 United States Jeff Borowiak 4 2
India Vijay Amritraj 4 4 United States Harold Solomon 6 6
United States Harold Solomon 6 6 United States Harold Solomon 4 1
United States Sandy Mayer 6 6 3 United States Vitas Gerulaitis 6 6
Romania Ilie Năstase 2 2 United States Sandy Mayer 4 6 3
Australia John Alexander 3 3 3 United States Vitas Gerulaitis 6 5 6
3 United States Vitas Gerulaitis 6 6 3 United States Vitas Gerulaitis 5 6 4 5
4 United States Eddie Dibbs 6 6 2 Sweden Björn Borg 6 5 6 6
Australia Ken Rosewall 3 4 4 United States Eddie Dibbs 3 2
South Africa Cliff Drysdale 6 6 South Africa Cliff Drysdale 6 6
United States Tim Gullikson 1 2 South Africa Cliff Drysdale 4 5
United States Dick Stockton 6 4 5 2 Sweden Björn Borg 6 6
Australia Tony Roche 5 6 6 Australia Tony Roche 4 2
Australia Rod Laver 4 2 2 Sweden Björn Borg 6 6
2 Sweden Björn Borg 6 6

References

  1. ^ "Borg and Gerulaitis Advance to Final". Las Vegas: The New York Times. 26 March 1978. Retrieved 27 October 2018. Borg was pushed to the limit by Cliff Drysdale, an added starter, before winning his semifinal, 6‐4, 6‐5, with a 7‐5 tiebreaker. Gerulaitis defeated Harold Solomon, 6‐4, 6‐1.
  2. ^ "Borg vexes Vitas". Las Vegas: The Hutchinson News. United Press International. 27 March 1978. p. 7. Retrieved 27 October 2018.