1864 United States presidential election in Delaware

From Wikipedia, the free encyclopedia

This is an old revision of this page, as edited by TEMPO156 (talk | contribs) at 20:41, 20 April 2020 (Corrected McClellan home state to NJ). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

1864 United States presidential election in Delaware

← 1860 November 8, 1864 1868 →
 
Nominee George B. McClellan Abraham Lincoln
Party Democratic National Union
Home state New Jersey Illinois
Running mate George H. Pendleton Andrew Johnson
Electoral vote 3 0
Popular vote 8,767 8,155
Percentage 51.81% 48.19%

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
Republican

The 1864 United States presidential election in Delaware took place on November 8, 1864, as part of the 1864 United States presidential election. Delaware voters chose 3 representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Delaware was won by the 4th Commanding General of the United States Army George B. McClellan (DPennsylvania), running with Representative George H. Pendleton, with 51.81% of the popular vote against the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 48.19% of the popular vote.[1]

Results

United States presidential election in Delaware, 1864[1]
Party Candidate Votes %
Democratic George B. McClellan 8,767 51.81%
National Union Abraham Lincoln 8,155 48.19%
Total votes 16,922 100.00%

References

  1. ^ a b c "1864 Presidential Election Results Delaware". {{cite web}}: Cite has empty unknown parameter: |1= (help)