Jump to content

Philpott Lake

Coordinates: 36°46′53″N 80°01′39″W / 36.78139°N 80.02750°W / 36.78139; -80.02750
From Wikipedia, the free encyclopedia

This is an old revision of this page, as edited by Ser Amantio di Nicolao (talk | contribs) at 00:10, 13 May 2020 (add authority control). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

Philpott Lake
LocationFranklin / Patrick / Henry counties, Virginia
Coordinates36°46′53″N 80°01′39″W / 36.78139°N 80.02750°W / 36.78139; -80.02750
TypeReservoir
Basin countriesUnited States
Surface area2,900 acres (1,200 ha)
Shore length1100 mi (160 km)
Surface elevation974 ft (297 m)
1 Shore length is not a well-defined measure.

Philpott Lake is a reservoir in the U.S. state of Virginia.[1] It is impounded by Philpott Dam.

The lake is at an elevation of 974 feet (297 m),[1] covers an area of 2,900 acres (12 km2), and has a shoreline length of 100 miles (160 km). Philpott Lake extends into Franklin, Henry, and Patrick counties, Virginia. It is bordered by 6,424 acres (26.00 km2) of U.S. Army Corps of Engineers-managed lands.[2]

The lake and Philpott Dam were created to control flooding along the Smith River, to generate hydroelectric power, and to provide recreational activities. Construction on Philpott Dam began in 1948 and was completed in 1952.[2]

See also

References

  1. ^ a b "Philpott Lake". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved January 4, 2017.
  2. ^ a b "F A Q". U. S. Army Corps of Engineers, Wilmington District. Archived from the original on February 8, 2012. Retrieved January 4, 2017.