1916 Vermont gubernatorial election
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Elections in Vermont |
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The 1916 Vermont gubernatorial election took place on November 7, 1916. Incumbent Republican Charles W. Gates, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Horace F. Graham defeated Democratic candidate William B. Mayo to succeed him.
Republican primary
Results
Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Republican | Horace F. Graham | 33,244 | 99.9 | ||
Republican | Other | 37 | 0.1 | ||
Total votes | '33,281' | '100' |
Democratic primary
Results
Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Democratic | William B. Mayo | 3,562 | 99.9 | ||
Democratic | Other | 1 | 0.0 | ||
Total votes | '3,563' | '100' |
General election
Results
Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Republican | Horace F. Graham | 43,265 | 71.1 | ||
Democratic | William B. Mayo | 15,789 | 25.9 | ||
Socialist | W. R. Rowland | 920 | 1.5 | ||
Prohibition | Lester W. Hanson | 876 | 1.4 | ||
N/A | Other | 4 | 0.0 | ||
Total votes | '60,854' | '100' |
References
- ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 1 January 2015.
- ^ a b "Primary Election Results" (PDF). Office of the Vermont Secretary of State. Retrieved 1 January 2015.
- ^ "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Retrieved 1 January 2015.