1864 United States presidential election in Delaware

Main article: 1864 United States presidential election

1864 United States presidential election in Delaware

November 8, 1864

Nominee George B. McClellan Abraham Lincoln Party Democratic National Union Home state New Jersey Illinois Running mate George H. Pendleton Andrew Johnson Electoral vote 3 0 Popular vote 8,767 8,155 Percentage 51.81% 48.19%

President before election Abraham Lincoln Republican Elected President Abraham Lincoln Republican

The 1864 United States presidential election in Delaware took place on November 8, 1864, as part of the 1864 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Delaware was won by the 4th Commanding General of the United States Army George B. McClellan (D–Pennsylvania), running with Representative George H. Pendleton, with 51.81% of the popular vote against the incumbent President Abraham Lincoln (R-Illinois), running with former Senator and Military Governor of Tennessee Andrew Johnson, with 48.19% of the popular vote.

Results

1864 United States presidential election in Delaware

Party		Candidate	Votes	%
	Democratic	George B. McClellan	8,767	51.81%
	National Union	Abraham Lincoln	8,155	48.19%
Total votes			16,922	100.00%

See also

• United States presidential elections in Delaware