Dangling else
The dangling else is a problem in computer programming in which an optional else clause in an if–then(–else) statement results in nested conditionals being ambiguous. Formally, the reference context-free grammar of the language is ambiguous, meaning there is more than one correct parse tree.
In many programming languages one may write conditionally executed code in two forms: the if-then form, and the if-then-else form – the else clause is optional:
if a then s if a then s1 else s2
This gives rise to an ambiguity in interpretation when there are nested statements, specifically whenever an if-then form appears as s1
in an if-then-else form:
if a then if b then s else s2
In this example, s
is unambiguously executed when a
is true and b
is true, but one may interpret s2
as being executed when a
is false (thus attaching the else to the first if) or when a
is true and b
is false (thus attaching the else to the second if). In other words, one may see the previous statement as either of the following expressions:
if a then (if b then s) else s2 or if a then (if b then s else s2)
The dangling else problem dates to ALGOL 60,[1] and has been resolved in various ways in subsequent languages. In LR parsers, the dangling else is the archetypal example of a shift-reduce conflict.
Avoiding ambiguity while keeping the syntax
This is a problem that often comes up in compiler construction, especially scannerless parsing. The convention when dealing with the dangling else is to attach the else to the nearby if statement,[2] allowing for unambiguous context-free grammars, in particular. Programming languages like Pascal[3] and C[4] follow this convention, so there is no ambiguity in the semantics of the language, though the use of a parser generator may lead to ambiguous grammars. In these cases alternative grouping is accomplished by explicit blocks, such as begin...end
in Pascal[5] and {...}
in C.
Depending on the compiler construction approach, one may take different corrective actions to avoid ambiguity:
- If the parser is produced by a SLR, LR(1) or LALR LR parser generator, the programmer will often rely on the generated parser feature of preferring shift over reduce whenever there is a conflict.[2] Alternatively, the grammar can be rewritten to remove the conflict, at the expense of an increase in grammar size (see below).
- If the parser is produced by a Pruning and Deep Pruning LR generator, one can issue directives that prune away the ambiguities completely.[6]
- If the parser is hand written, the programmer may use a non-ambiguous context-free grammar. Alternatively, one may rely on a non-context-free grammar or a parsing expression grammar.
Avoiding ambiguity by changing the syntax
The problem can also be solved by making explicit the link between an else and its if, within the syntax. This usually helps avoid human errors.[7] Possible solutions are:
- Having an "end if" statement. Examples of such languages are ALGOL 68, Ada, Eiffel, PL/SQL, Visual Basic, and Modula-2.
- Disallowing the statement following a "then" to be an "if" itself (it may however be a pair of statement brackets containing nothing but an if-then-clause). This approach is followed by ALGOL 60[8] and Python.[9]
- Requiring braces (parenthesizing) when an "else" follows an "if".[10]
- Requiring every "if" to be paired with an "else".
Examples
Concrete examples follow.
C
In C, the grammar reads in part:
statement = ... | selection-statement selection-statement = ... | IF ( expression ) statement | IF ( expression ) statement ELSE statement
Thus, without further rules, the statement
if (a) if (b) s; else s2;
could ambiguously be parsed as if it were either:
if (a) {
if (b)
s;
else
s2;
}
or as:
if (a) {
if (b)
s;
}
else
s2;
In practice in C the first tree is chosen, by associating the else
with the nearest if
.
Avoiding the conflict in LR parsers
The above example could be rewritten in the following way to remove the ambiguity:
statement = ... | selection-statement statement-with-else = ... | selection-statement-with-else selection-statement = ... | IF ( expression ) statement | IF ( expression ) statement-with-else ELSE statement selection-statement-with-else = ... | IF ( expression ) statement-with-else ELSE statement-with-else
Any other statement related grammar rules may also have to be duplicated in this way if they may directly or indirectly end with a statement
or selection-statement
non-terminal.
See also
References
- ^ Attention: This template ({{cite doi}}) is deprecated. To cite the publication identified by doi:10.1145/365813.365821, please use {{cite journal}} (if it was published in a bona fide academic journal, otherwise {{cite report}} with
|doi=10.1145/365813.365821
instead. - ^ a b 5.2 Shift/Reduce Conflicts from GNU Operating System web site
- ^ ISO 7185:1990 (Pascal) 6.8.3.4: An if-statement without an else-part shall not be immediately followed by the token else.
- ^ ISO 9899:1999 (C): 6.8.4.1(3): "An else is associated with the lexically nearest preceding if that is allowed by the syntax.", available at WG14 N1256, p. 134
- ^ Pascal, Nell Dale and Chip Weems, "Dangling Else", p. 160–161
- ^ http://www.mightyheave.com/blog/?p=17#more-17
- ^ Ambiguity of dangling else: non-context-free grammars are semantically opaque
- ^ 4.5.1 Conditional Statements — Syntax in P. Nauer (ed.), Revised Report on the Algorithmic Language ALGOL 60, CACM 6,1, 1963 pp. 1-17
- ^ The Python Language Reference, 9. Full Grammar specification
- ^ Ambiguity of dangling else: require braces when else follows if