|Full name||Henry Clinton Attenburrow|
|Born||19 September 1807
|Died||25 September 1881
Saint Brélade, Jersey
|Bowling style||Right-arm underarm slow|
|Domestic team information|
|1848||Nottingham Cricket Club|
Source: Cricinfo, 20 February 2013
Henry Clinton Attenburrow (19 September 1807 – 25 September 1881) was an English cricketer. Attenburrow's batting style is unknown, though it is known he bowled right-arm underarm slow. He was born at Nottingham, Nottinghamshire.
Attenburrow made a single first-class appearance for Nottinghamshire against England in 1847 at Trent Bridge. In England's first-innings of 105 all out, Attenburrow took four wickets. He opened the batting in Nottinghamshire's first-innings of 176 all out, scoring 3 runs before he was dismissed by Tom Hunt. In England's second-innings of 82 all out, he took six wickets. Nottinghamshire were set twelve runs for victory, reaching their target without losing a wicket. The following season he made a single first-class appearance for Nottingham Cricket Club against Sheffield Cricket Club at Trent Bridge. In Sheffield's first-innings of 111 all out, Attenburrow took three wickets, while in Nottingham's first-innings of 36 all out he batted at number ten, where he was dismissed for a duck by Tom Hunt. He took two wickets in Sheffield's second-innings of 81 all out, which set Nottingham a target of 157 for victory. Nottingham were dismissed for 71 in their chase, with Attenburrow again dismissed for a duck by Hunt.