Le Rochereau

From Wikipedia, the free encyclopedia
Jump to: navigation, search
Le Rochereau
Le Rochereau is located in France
Le Rochereau
Le Rochereau
Coordinates: 46°42′25″N 0°09′14″E / 46.7069°N 0.1539°E / 46.7069; 0.1539Coordinates: 46°42′25″N 0°09′14″E / 46.7069°N 0.1539°E / 46.7069; 0.1539
Country France
Region Nouvelle-Aquitaine
Department Vienne
Arrondissement Poitiers
Canton Vouneuil-sous-Biard
Area1 8.93 km2 (3.45 sq mi)
Population (2006)2 676
 • Density 76/km2 (200/sq mi)
Time zone CET (UTC+1)
 • Summer (DST) CEST (UTC+2)
INSEE/Postal code 86208 /86170
Elevation 110–148 m (361–486 ft)
(avg. 123 m or 404 ft)

1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km² (0.386 sq mi or 247 acres) and river estuaries.

2 Population without double counting: residents of multiple communes (e.g., students and military personnel) only counted once.

Le Rochereau is a former commune in the Vienne department in the Nouvelle-Aquitaine region in western France. On 1 January 2017, it was merged into the new commune Champigny en Rochereau.[1]

See also[edit]


  1. ^ Arrêté préfectoral 19 July 2016 (French)