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In geometry, a radiodrome is the pursuit curve followed by a point that is pursuing another linearly-moving point. The term is derived from the Greek words "ῥάδιος" (easier) and "δρόμος" (running). The classic (and best-known) form of a radiodrome is known as the "dog curve"; this is the path a dog follows when it swims across a stream with a current after food it has spotted on the other side. Because the dog drifts downwards with the current, it will have to change its heading; it will also have to swim further than if it had computed the optimal heading. This case was described by Pierre Bouguer in 1732.

A radiodrome may alternatively be described as the path a dog follows when chasing a hare, assuming that the hare runs in a straight line at a constant velocity. It is illustrated by the following figure:

Graph of a radiodrome, also known as a dog curve
The path of a dog chasing a hare running along a vertical straight line at a constant speed. The dog runs towards the momentary position of the hare, and will have to be changing his heading continuously. The speed of the dog is 20% faster than the speed of the hare.

Mathematical analysis[edit]

Introduce a coordinate system with origin at the position of the dog at time zero and with y-axis in the direction the hare is running with the constant speed . The position of the hare at time zero is (Ax, Ay) and at time t it is






The dog runs with the constant speed towards the instantaneous position of the hare.

The differential equation corresponding to the movement of the dog, (x(t), y(t)), is consequently











It is possible to obtain a closed-form analytic expression y=f(x) for the motion of the dog, From (2) and (3) it follows that






Multiplying both sides with and taking the derivative with respect to x using that






one gets












From this relation it follows that






where B is the constant of integration determined by the initial value of y' at time zero, y' (0)= sinh(B − (Vt /Vd) lnAx), i.e.,






From (8) and (9) it follows after some computations that






If, now, Vt ≠ Vd, this relation integrates to






where C is the constant of integration.

If Vt = Vd, one gets instead






If Vt < Vd, it follows from (11) that






In the case illustrated in the figure above, VtVd = 11.2 and the chase starts with the hare at position (Ax, −0.6 Ax) which means that y'(0) = −0.6. From (13) it thus follows that the hare is caught at position (Ax, 1.21688Ax), and consequently that the hare will have run the total distance (1.21688 + 0.6) Ax before being caught. The arclength of the dog's path is (13) multiplied by VdVt =1.2 .

If Vt ≥ Vd, one has from (11) and (12) that , which means that the hare will never be caught, whenever the chase starts.

See also[edit]