1884 United States presidential election in Maine
Appearance
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
|
Elections in Maine |
---|
The 1884 United States presidential election in Maine took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.
Maine voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a margin of 15.37%.
Results
United States presidential election in Maine, 1884[1] | ||||||||
---|---|---|---|---|---|---|---|---|
Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | James Gillespie Blaine of Maine | John Alexander Logan of Illinois | 72,217 | 55.34% | 6 | 100.00% | ||
Democratic | Grover Cleveland of New York | Thomas Andrews Hendricks of Indiana | 52,153 | 39.97% | 0 | 0.00% | ||
Greenback | Benjamin Franklin Butler of Massachusetts | Absolom Madden West of Mississippi | 3,955 | 3.03% | 0 | 0.00% | ||
Prohibition | John Pierce St. John of Kansas | William Daniel of Maryland | 2,160 | 1.65% | 0 | 0.00% | ||
N/A | Others | Others | 6 | 0.01% | 0 | 0.00% | ||
Total | 130,491 | 100.00% | 6 | 100.00% |