∂ ( ψ , ∇ 2 ψ ) ∂ ( x , y ) {\displaystyle {\frac {\partial (\psi ,\nabla ^{2}\psi )}{\partial (x,y)}}}
A e f f = λ 2 4 π × G {\displaystyle A_{eff}={\frac {\lambda ^{2}}{4\pi }}\times G}
d B i = 10 log ( G ) = 10 log ( 4 π A λ 2 ) {\displaystyle dBi=10\log(G)=10\log({\frac {4\pi A}{\lambda ^{2}}})}
T C = 5 9 ( T F − 32 ) {\displaystyle T_{C}={\frac {5}{9}}(T_{F}-32)} Δ T C = T C 1 − T C 2 = 5 9 ( T F 1 − 32 ) − 5 9 ( T F 2 − 32 ) = 5 9 ( T F 1 − 32 − T F 2 + 32 ) = 5 9 ( T F 1 − T F 2 + 32 − 32 ) = 5 9 Δ T F {\displaystyle \Delta T_{C}=T_{C_{1}}-T_{C_{2}}={\frac {5}{9}}(T_{F_{1}}-32)-{\frac {5}{9}}(T_{F_{2}}-32)={\frac {5}{9}}(T_{F_{1}}-32-T_{F_{2}}+32)={\frac {5}{9}}(T_{F_{1}}-T_{F_{2}}+32-32)={\frac {5}{9}}\Delta T_{F}}
1 μ ∇ × B → = J → + ϵ ∂ E → ∂ t {\displaystyle {\frac {1}{\mu }}\nabla \times {\vec {B}}={\vec {J}}+\epsilon {\frac {\partial {\vec {E}}}{\partial t}}}
ϵ ∂ E → ∂ t {\displaystyle \epsilon {\frac {\partial {\vec {E}}}{\partial t}}}
J → {\displaystyle {\vec {J}}}
V i n d = 2 π f μ 0 H x {\displaystyle V_{ind}=2\pi f\mu _{0}H_{x}}
