User:VonHaarberg/sandbox
This is a list of notable implementations of the Fizz Buzz game. The task to come up with an implementation for this game is hardly a challenge for routined programmers and therefore often used as screening test in interview situations.
Fizz Buzz implementations by programming language[edit]
JavaScript[edit]
A details version using JavaScript:
// Initialize a string variable for the output
var output = '';
// Count to 100 using i as the counter
for (var i = 1; i <= 100; i++) {
// If i is not divisible by 3 or 5, append the number itself.
// Note: In JavaScript, non-zero integers are considered as
// truthy values, therefore if there's a remainder on both,
// we append the number instead.
if (i % 5 && i % 3) {
output += i + ' ';
}
// If i is divisible by 3 with no remainder, append Fizz
if (i % 3 === 0) {
output += 'Fizz ';
}
// If i is divisible by 5 with no remainder, append Buzz
if (i % 5 === 0) {
output += 'Buzz ';
}
}
// Print the output to the console
console.log(output);
A shorter version:
var o='';
for (var i=1; i<=100; i++) {
i%3 || (o+='Fizz ');
i%5 || (o+='Buzz ');
!(i%3 && i%5) || (o+=(i+' '));
}
console.log(o);
F#[edit]
An implementation in F#
let to_string i = match i%3, i%5 with
| 0,0 -> "FizzBuzz"
| 0,_ -> "Fizz"
| _,0 -> "Buzz"
| _ -> string i
for i in 1..100 do
printfn "%s" (to_string i)
C++[edit]
Using template metaprogramming in C++:
// Helper macros to make compiler output a bit more readable, but keep the
// source readable too.
#define List _
#define Integer __
template <int Condition, typename A, typename B>
struct If;
template <typename A, typename B>
struct If<true, A, B> {
typedef A result;
};
template <typename A, typename B>
struct If<false, A, B> {
typedef B result;
};
struct Nil {};
struct Fizz {};
struct Buzz {};
struct FizzBuzz {};
template <int N>
struct Integer {
static const int value = N;
};
template <typename Head, typename Rest>
struct List {
typedef Head head;
typedef Rest rest;
};
template <typename Container, typename Value>
struct PushFront {
typedef List<Value, Container> result;
};
template <int N>
struct IntToFizzBuzz {
typedef typename If<
N % 15 == 0, FizzBuzz,
typename If<N % 3 == 0, Fizz, typename If<N % 5 == 0, Buzz, Integer<N>>::
result>::result>::result result;
};
template <int N>
struct DoFizzBuzz {
typedef typename PushFront<typename IntToFizzBuzz<N>::result,
typename DoFizzBuzz<N - 1>::result>::result result;
};
template <>
struct DoFizzBuzz<0> {
typedef Nil result;
};
template <typename T>
struct Print;
Print<DoFizzBuzz<100>::result> ___;
// Will print when attempting to compile with gcc 5.4:
// fizzbuzz.cc:61:32: error: aggregate ‘Print<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<_<Nil, __<1> >, __<2> >, Fizz>, __<4> >, Buzz>, Fizz>, __<7> >, __<8> >, Fizz>, Buzz>, __<11> >, Fizz>, __<13> >, __<14> >, FizzBuzz>, __<16> >, __<17> >, Fizz>, __<19> >, Buzz>, Fizz>, __<22> >, __<23> >, Fizz>, Buzz>, __<26> >, Fizz>, __<28> >, __<29> >, FizzBuzz>, __<31> >, __<32> >, Fizz>, __<34> >, Buzz>, Fizz>, __<37> >, __<38> >, Fizz>, Buzz>, __<41> >, Fizz>, __<43> >, __<44> >, FizzBuzz>, __<46> >, __<47> >, Fizz>, __<49> >, Buzz>, Fizz>, __<52> >, __<53> >, Fizz>, Buzz>, __<56> >, Fizz>, __<58> >, __<59> >, FizzBuzz>, __<61> >, __<62> >, Fizz>, __<64> >, Buzz>, Fizz>, __<67> >, __<68> >, Fizz>, Buzz>, __<71> >, Fizz>, __<73> >, __<74> >, FizzBuzz>, __<76> >, __<77> >, Fizz>, __<79> >, Buzz>, Fizz>, __<82> >, __<83> >, Fizz>, Buzz>, __<86> >, Fizz>, __<88> >, __<89> >, FizzBuzz>, __<91> >, __<92> >, Fizz>, __<94> >, Buzz>, Fizz>, __<97> >, __<98> >, Fizz>, Buzz> > ___’ has incomplete type and cannot be defined
// Print<DoFizzBuzz<100>::result> ___;
// ^
Perl 6[edit]
A FizzBuzzWoof implementation in Perl 6:
my @numbers = (0..1000);
for @numbers -> $x {
given $x {
when $x % 105 == 0 {
say "FizzBuzzWoof"
}
when $x % 15 == 0 {
say "FizzBuzz"
}
when $x % 21 == 0 {
say "FizzWoof"
}
when $x % 35 == 0 {
say "BuzzWoof"
}
when $x % 3 == 0 {
say "Fizz"
}
when $x % 5 == 0 {
say "Buzz"
}
when $x % 7 == 0 {
say "Woof"
}
default {
say $x
}
}
}
Python[edit]
print ['Fizz'*(i%3<1)+'Buzz'*(i%5<1) or i for i in range(1,101)]