User talk:Siveshwar

Welcome to Wikipedia

Hello shiveswar....Welcome to wikipedia....Hope that you learn a lot from wikipedia as well contribute and share your knowledge with others, thus helping for the betterment of the society.....Ganeshsashank (talk) 17:01, 8 February 2010 (UTC)

Solve these questions

Verify green's theorem for the following by evaluating both the integrals:

Q.1) $\oint _{C}x^{3}dy-y^{3}dx\,\!$

where C is the circle $x=2cos\theta \,\!$ and $y=2sin\theta \,\!$ where $0\leq \theta \leq 2\pi \,\!$

Q.2) $\oint _{C}(x+y)dx+x^{2}dy\,\!$ where C is the triangle with the vertices $(0,0);(2,0);(2,4)\,\!$ taken in that order.

Q.3) Evaluate the integral for the lemniscate along X-axis.

$\int \int {\frac {r}{\sqrt {(a^{2}+r^{2})}}}drd\theta \,\!$

where ${\frac {-\pi }{4}}\leq \theta \leq {\frac {\pi }{4}}\,\!$ and $0\leq r\leq acos2\theta \,\!$ Ganeshsashank (talk) 08:39, 21 February 2010 (UTC)

Doubt On schrödinger wave equation

Hai shiva, when we derive the Schrödinger wave equation, we derive it with repect to time. But, during the explanation for $\alpha \,\!$-Decay, we take the wave equtaion with respect to distance. So, my doubt is

Can we take the wave funtion $\psi \,\!$'s derivative with respect to any fundamental parameter??

Schrödinger's time dependent wave equation is:

$\nabla ^{2}\psi +{\frac {2m(E-V)}{\hbar ^{2}}}\psi =0\,\!$

And the schrödinger's equation taken during evaluation of single step is:

${\frac {\partial ^{2}\psi }{\partial ^{2}x^{2}}}+{\frac {2m(E-V_{0})}{\hbar ^{2}}}\psi =0\,\!$

Answer me: Can we do like this?? Ganeshsashank (talk) 14:43, 23 February 2010 (UTC)

Ok dude, I got it...

When we use $\nabla ^{2}\,\!$, it can be with respect to any thing whether ${\frac {\partial ^{2}}{\partial t^{2}}}\,\!$ or ${\frac {\partial ^{2}}{\partial x^{2}}}\,\!$. Here $\nabla ^{2}\,\!$ is just an operator. —Preceding unsigned comment added by Ganeshsashank (talk • contribs) 09:42, 25 February 2010 (UTC)