1804 United States presidential election in New York
(Redirected from 1804 US presidential election in New York)
 | |||||||||||||||||||||||
| |||||||||||||||||||||||
| |||||||||||||||||||||||
| |||||||||||||||||||||||
| Elections in New York State |
|---|
 |
The 1804 United States presidential election in New York took place between November 2 and December 5, 1804, as part of the 1804 United States presidential election. The state legislature chose 19 representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, New York cast 19 electoral votes for Democratic Republican incumbent Thomas Jefferson.[1]
See also
[edit]References
[edit]- ^ Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson: McFarland & Company. p. 12. ISBN 9780786410170.
| Candidates |  | |
|---|---|---|
| General articles | ||
| Local results | ||
| Other 1804 elections | ||
  | This New York elections-related article is a stub. You can help Wikipedia by expanding it. |