Liberty Township, Shelby County, Indiana

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Liberty Township
Township
Map highlighting Liberty Township, Shelby County, Indiana.svg
Coordinates: 39°28′59″N 85°39′52″W / 39.48306°N 85.66444°W / 39.48306; -85.66444Coordinates: 39°28′59″N 85°39′52″W / 39.48306°N 85.66444°W / 39.48306; -85.66444
Country United States
State Indiana
County Shelby
Government
 • Type Indiana township
Area
 • Total 23.59 sq mi (61.1 km2)
 • Land 23.58 sq mi (61.1 km2)
 • Water 0.01 sq mi (0.03 km2)
Elevation[1] 850 ft (259 m)
Population (2010)
 • Total 1,772
 • Density 75.2/sq mi (29.0/km2)
FIPS code 18-43398[2]
GNIS feature ID 453561

Liberty Township is one of fourteen townships in Shelby County, Indiana. As of the 2010 census, its population was 1,772 and it contained 723 housing units.[3]

Geography[edit]

According to the 2010 census, the township has a total area of 23.59 square miles (61.1 km2), of which 23.58 square miles (61.1 km2) (or 99.96%) is land and 0.01 square miles (0.026 km2) (or 0.04%) is water.[3]

References[edit]

  1. ^ "US Board on Geographic Names". United States Geological Survey. 2007-10-25. Retrieved 2008-01-31. 
  2. ^ "American FactFinder". United States Census Bureau. Retrieved 2008-01-31. 
  3. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Retrieved 2013-05-10. 

External links[edit]