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True airspeed

Doesn't a mach number represent indicated airspeed over speed of sound? Seeing as how speed of sound is already a function of pressure, and true airspeed is also a function of pressure, by calling it "true airspeed over speed of sound", you're effectively dividing by static pressure twice. moeburn (talk) 03:37, 29 March 2016 (UTC)[reply]

Revision as of 03:36, 29 March 2016 edit SineBot (talk \| contribs) Bots 2,549,029 edits m Signing comment by Moeburn - "→‎True airspeed: new section" ← Previous edit		Revision as of 03:37, 29 March 2016 edit undo Moeburn (talk \| contribs) 161 edits →‎True airspeed Next edit →
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	== True airspeed ==		== True airspeed ==

	Doesn't a mach number represent ''indicated'' airspeed over speed of sound? Seeing as how speed of sound is already a function of pressure, by calling it "true airspeed over speed of sound", you're effectively dividing by static pressure twice. ~~<small><span class="autosigned">— Preceding [[Wikipedia:Signatures\|unsigned]] comment added by~~ [[User:Moeburn\|~~Moeburn~~]] ([[User talk:Moeburn\|talk~~]] • [[Special:Contributions/Moeburn\|contribs~~]]) 03:36, 29 March 2016 (UTC)~~</span></small><!-- Template:Unsigned --> <!--Autosigned by SineBot-->~~		Doesn't a mach number represent ''indicated'' airspeed over speed of sound? Seeing as how speed of sound is already a function of pressure, and true airspeed is also a function of pressure, by calling it "true airspeed over speed of sound", you're effectively dividing by static pressure twice. [[User:Moeburn\|moeburn]] ([[User talk:Moeburn\|talk]]) 03:37, 29 March 2016 (UTC)