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Software: Computing

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Multiuser calls cannot be encrypted?

there is a rumor that multiuser calls cannot be encrypted. https://www.reddit.com/r/riotim/comments/cht2me/are_calls_via_riot_end_to_end_encrypted/

I could not locate a good source for this Disoff (talk) 23:44, 10 February 2020 (UTC)[reply]

Encrypted by default

@134.100.186.60:, afaik from the linked source, https://github.com/vector-im/riot-web/issues/6779, riot still seems unencrypted by default. However, tot feel free to provide a newer/better source! Ancecdotally, from playing around with riot on my device, the rooms i made were not encrypted by default.

I just found out i cannot ping an unregisterd user, taking talk to their talk pg! --Disoff (talk) 01:14, 10 April 2020 (UTC)Italic text[reply]

@@ Line 17: / Line 17: @@
 {{reply to|134.100.186.60}}, afaik from the linked source, https://github.com/vector-im/riot-web/issues/6779, riot still seems unencrypted by default. However, tot feel free to provide a newer/better source! Ancecdotally, from playing around with riot on my device, the rooms i made were not encrypted by default.
+I just found out i cannot ping an unregisterd user, taking talk to their talk pg!
-Uhh, can i ping a non user?
 ''--[[User:Disoff|Disoff]] ([[User talk:Disoff|talk]]) 01:14, 10 April 2020 (UTC)Italic text''