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This is an old revision of this page, as edited by Paraboloid01 (talk | contribs) at 12:20, 19 June 2022 (→‎Kinetic energy formula is wrong only in specific case/example). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

What does most of that stuff have to do with improving the X87 article? -- AnonMoos (talk) 15:01, 6 September 2012 (UTC)[reply]

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Hello. In case you didn't know, when you add content to talk pages and Wikipedia pages that have open discussion, you should sign your posts by typing four tildes ( ~~~~ ) at the end of your comment. You could also click on the signature button or located above the edit window. This will automatically insert a signature with your username or IP address and the time you posted the comment. This information is useful because other editors will be able to tell who said what, and when they said it. Thank you. --SineBot (talk) 12:12, 11 September 2012 (UTC)[reply]

Your recent edits

Hello. In case you didn't know, when you add content to talk pages and Wikipedia pages that have open discussion, you should sign your posts by typing four tildes ( ~~~~ ) at the end of your comment. You could also click on the signature button or located above the edit window. This will automatically insert a signature with your username or IP address and the time you posted the comment. This information is useful because other editors will be able to tell who said what, and when they said it. Thank you. --SineBot (talk) 13:40, 4 October 2012 (UTC)[reply]

Your recent edits

Hello. In case you didn't know, when you add content to talk pages and Wikipedia pages that have open discussion, you should sign your posts by typing four tildes ( ~~~~ ) at the end of your comment. You could also click on the signature button or located above the edit window. This will automatically insert a signature with your username or IP address and the time you posted the comment. This information is useful because other editors will be able to tell who said what, and when they said it. Thank you. --SineBot (talk) 19:40, 9 October 2012 (UTC)[reply]

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Information icon Please refrain from using talk pages such as Talk:Kinetic energy for general discussion of the topic or other unrelated topics. They are for discussion related to improving the article in specific ways, based on reliable sources and the project policies and guidelines; they are not for use as a forum or chat room. If you have specific questions about certain topics, consider visiting our reference desk and asking them there instead of on article talk pages. See here for more information. Thank you. - DVdm (talk) 21:20, 14 June 2022 (UTC)[reply]

Kinetic energy formula is wrong only in specific case/example

I read about kinetic energy realativity in Talk:Kinetic energy Archive_1 and understood, that there no easy possible way of proving that kinetic energy formula is wrong... But there is one example where you can safe 1/4 of energy with rocket, which consist of two parts.
Let's say there in cosmos we want sent not moving rocket, which consist of two parts: of part A and part B. Each rocket part is rocket and have mass 1 kg. Part A carring itself and part B and accelerates from 0 m/s to 10 m/s. For this need energy Now part B separates from part A (both parts have speed 10 m/s) and reaches 20 m/s. But part B from part A reference frame, have speed 0 m/s, so for part B to reach 20 m/s need energy For part A to accelerate from 0 to 20 m/s need energy Total energy needed for part A to accelerate itself to 20 m/s and part B to 10 m/s is 200+50=250 (J). And for part B to accelerate from 10 m/s to 20 m/s need energy 50 (J). So total need for both rocket parts 250+50=300 (J) of energy.
Now if accelerate separatly 1 kg mass rocket A to 20 m/s and 1 kg mass rocket B to 20 m/s need energy for each And total needed energy for rocket A and rocket B to accelerate to 20 m/s is 200+200=400 (J). So we saving 400-300=100 (J) depending in what manner we accelerating rockets (and in both cases rockets reach 20 m/s and have same ~1 kg mass). Say part A of first rocket flying to Moon and part B of first rocket flying to Mars. And rocket A flying to Moon and rocket B flying to Mars. Assuming Moon and Mars is almost in same direction. We saving 1/4 of energy and reaching we same speeds for all parts and rockets. 1/4 energy saving is maximum for two parts rocket. For more parts rocket there, I think, possible to save little bit more than 1/4 energy (but much energy you will not save). Paraboloid01