1948 U.S. National Championships – Women's singles
Appearance
Women's singles | |
---|---|
1948 U.S. National Championships | |
Champion | Margaret Osborne duPont[1] |
Runner-up | Louise Brough |
Score | 4–6, 6–4, 15–13 |
Third-seeded Margaret Osborne duPont defeated Louise Brough 4–6, 6–4, 15–13 in the final to win the Women's Singles tennis title at the 1948 U.S. National Championships.[1][2]
Seeds
The seven seeded U.S. players are listed below. Margaret Osborne duPont is the champion; others show in brackets the round in which they were eliminated.[3]
- Louise Brough (Finalist)
- Doris Hart (Quarterfinalist)
- Margaret Osborne duPont (Champion)
- Pat Canning Todd (Semifinalist)
- Shirley Fry (Third round)
- Beverly Baker (Quarterfinalist)
- Gussy Moran (Semifinalist)
Draw
Key
- Q = Qualifier
- WC = Wild Card
- LL = Lucky Loser
- r. = retired
Final Eight
Quarterfinals | Semifinals | Finals | ||||||||||||||||||
7 | Gussy Moran | 6 | 6 | |||||||||||||||||
2 | Doris Hart | 4 | 4 | |||||||||||||||||
7 | Gussy Moran | 8 | 4 | |||||||||||||||||
3 | Margaret Osborne duPont | 10 | 6 | |||||||||||||||||
3 | Margaret Osborne duPont | 1 | 6 | 6 | ||||||||||||||||
Beverly Baker | 6 | 2 | 0 | |||||||||||||||||
3 | Margaret Osborne duPont | 4 | 6 | 15 | ||||||||||||||||
1 | Louise Brough | 6 | 4 | 13 | ||||||||||||||||
1 | Louise Brough | 6 | 6 | |||||||||||||||||
Virginia Kovacs | 3 | 2 | ||||||||||||||||||
1 | Louise Brough | 6 | 6 | |||||||||||||||||
4 | Pat Canning Todd | 3 | 3 | |||||||||||||||||
4 | Pat Canning Todd | 6 | 6 | |||||||||||||||||
Madge Vosters | 3 | 1 |
References
- ^ a b Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
- ^ "Exciting Game for Tennis Title". Cairns Post (Qld. : 1909 - 1954). Qld.: National Library of Australia. 21 September 1948. p. 1.
- ^ G.P. Hughes, ed. (1949). Dunlop Lawn Tennis Annual and Almanack 1949. London: Ed. J. Burrow & Co. Ltd. pp. 159–164.