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1970 Pepsi-Cola Masters – Singles

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Singles
1970 Pepsi-Cola Masters
Final
ChampionUnited States Stan Smith
Runner-upAustralia Rod Laver
Score4–6, 6–3, 6–4
Events
Singles Doubles
ATP Finals · 1971 →

Stan Smith won the singles title at the 1970 Pepsi-Cola Masters. He defeated runner-up Rod Laver, although both had achieved the same number of wins.[1][2]

Round robin

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Key

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Australia Rosewall Socialist Federal Republic of Yugoslavia Franulović United States Ashe United States Smith Australia Laver Czechoslovakia Kodeš
Australia Ken Rosewall 6–3, 6–3 6–3, 6–4 4–6, 5–6 6–5, 3–6, 5–6 6–5, 6–4
Socialist Federal Republic of Yugoslavia Željko Franulović 3–6, 3–6 5–6, 6–3, 2–6 1–6, 6–5, 1–6 5–6, 6–3, 2–6 6–2, 3–6, 6–3
United States Arthur Ashe 3–6, 4–6 6–5, 3–6, 6–2 3–6, 6–3, 6–5 3–6, 2–6 6–3, 4–6, 6–3
United States Stan Smith 6–4, 6–5 6–1, 5–6, 6–1 6–3, 3–6, 5–6 4–6, 6–3, 6–4 6–3, 6–5
Australia Rod Laver 5–6, 6–3, 6–5 6–5, 3–6, 6–2 6–3, 6–2 6–4, 3–6, 4–6 6–4, 6–3
Czechoslovakia Jan Kodeš 5–6, 4–6 2–6, 6–3, 3–6 3–6, 6–4, 3–6 3–6, 5–6 4–6, 3–6

Standings

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Player RR W-L Sets W-L Games W-L Standings
United States Stan Smith
4–1
9–4
71–53
1
Australia Rod Laver
4–1
9–4
69–55
2
Australia Ken Rosewall
3–2
6–4
59–51
3
United States Arthur Ashe
3–2
6–7
58–53
4
Socialist Federal Republic of Yugoslavia Željko Franulović
1–4
5–9
55–70
5
Czechoslovakia Jan Kodeš
0–5
2–10
47–67
6

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

See also

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References

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  1. ^ John Barrett, ed. (1971). World of Tennis '71. London: Queen Anne Press. p. 134. ISBN 978-0-362-00091-7.
  2. ^ "Smith Bows to Ashe, but Wins Round-Robin Tennis in Tokyo". The New York Times. 15 December 1970.
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