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1884 United States presidential election in Wisconsin

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1884 United States presidential election in Wisconsin

← 1880 November 4, 1884 1888 →
 
Nominee James G. Blaine Grover Cleveland
Party Republican Democratic
Home state Maine New York
Running mate John A. Logan Thomas A. Hendricks
Electoral vote 11 0
Popular vote 161,135 146,453
Percentage 50.38% 45.79%

County Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Wisconsin was held on November 4, 1884 as part of the 1884 United States presidential election. State voters chose eleven electors to the Electoral College, who voted for president and vice president.

Republican Party candidate James G. Blaine won Wisconsin with 50.38 percent of the popular vote, winning the state's eleven electoral votes.[1]

Results

Presidential Candidate Running Mate Party Electoral Vote (EV) Popular Vote (PV)
James G. Blaine of Maine John A. Logan Republican 11 161,135 50.38%
Grover Cleveland Thomas A. Hendricks Democratic 0 146,453 45.79%
John St. John William Daniel Prohibition 0 7,649 2.39%
Benjamin Butler Absolom West Greenback 0 4,598 1.44%

References

  1. ^ "1884 Presidential General Election Results – Wisconsin". Retrieved August 18, 2016.