Jump to content

1908 United States presidential election in Iowa

From Wikipedia, the free encyclopedia

This is an old revision of this page, as edited by B.Perrine (talk | contribs) at 17:56, 15 January 2020. The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

1908 United States presidential election in Iowa

← 1904 November 3, 1908 1912 →
 
Nominee William Howard Taft William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate James S. Sherman John Worth Kern
Electoral vote 13 0
Popular vote 275,209 200,771
Percentage 55.62% 40.58%

President before election

Theodore Roosevelt
Republican

Elected President

William Howard Taft
Republican

The 1908 United States presidential election in Iowa took place on November 3, 1908. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.

Iowa voted for the Republican nominee, Secretary of War William Howard Taft, over the Democratic nominee, former U.S. Representative William Jennings Bryan. Taft won the state by a margin of 15.04%.

Results

1908 United States presidential election in Iowa[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican William Howard Taft of Ohio James Schoolcraft Sherman of New York 275,209 55.62% 13 100.00%
Democratic William Jennings Bryan of Nebraska John Worth Kern of Indiana 200,771 40.582% 0 0.00%
Prohibition Eugene Wilder Chafin of Illinois Aaron Sherman Watkins of Ohio 9,837 1.99% 0 0.00%
Socialist Eugene Victor Debs of Indiana Benjamin Hanford of New York 8,287 1.67% 0 0.00%
Independence Thomas Louis Hisgen of Massachusetts John Temple Graves of Georgia 404 0.08% 0 0.00%
Populist Thomas Edward Watson of Georgia Samuel Wardell Williams of Indiana 261 0.05% 0 0.00%
Total 494,769 100.00% 13 100.00%

References

  1. ^ "1908 Presidential General Election Results - Iowa". U.S. Election Atlas. Retrieved 23 December 2013.