1852 United States presidential election in Delaware
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Elections in Delaware |
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The 1852 United States presidential election in Delaware took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.
Delaware voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Delaware by a margin of 0.19%.
Results
United States presidential election in Delaware, 1852[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Franklin Pierce of New Hampshire | William R. King of Alabama | 6,318 | 49.85% | 3 | 100.00% | ||
Whig | Winfield Scott of New Jersey | William Alexander Graham of North Carolina | 6,293 | 49.66% | 0 | 0.00% | ||
Free Soil | John P. Hale of New Hampshire | George Washington Julian of Indiana | 62 | 0.49% | 0 | 0.00% | ||
Total | 12,673 | 100.00% | 3 | 100.00% |
References
- ^ "1852 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 17 March 2015.