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1792 United States presidential election in Delaware

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United States presidential election in Delaware, 1792

← 1789 November 2 – December 5, 1792 1796 →
 
Nominee George Washington John Adams
Party Nonpartisan Federalist
Home state Virginia Massachusetts
Electoral vote 3 3
Percentage 100%

President before election

George Washington
Nonpartisanism

Elected President

George Washington
Nonpartisanism

The 1792 United States presidential election in Delaware took place between November 2 and December 5, 1792 as part of the 1792 United States presidential election. The state legislature chose 3 members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Delaware's 3 electors each cast 1 vote for the incumbent, George Washington, and 1 vote for John Adams, the incumbent Vice President.[1]

Results

United States presidential election in Delaware, 1792
Party Candidate Votes Percentage Electoral votes
Nonpartisan George Washington 100.00% 3
Totals 100.00% 3

References

  1. ^ Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.