1958 NFL playoffs
The 1958 National Football League season resulted in a tie for the Eastern Conference championship between the Cleveland Browns and the New York Giants, requiring a one-game playoff to be held between them. This conference championship game was played on December 21, 1958, at Yankee Stadium. The winner of that game then hosted the Baltimore Colts on December 28.
Tournament bracket
| Eastern Conference playoff | NFL Championship | ||||||||
| W | Baltimore Colts | 23 (OT) | |||||||
| E | Cleveland Browns | 0 | E | New York Giants | 17 | ||||
| E | New York Giants | 10 | |||||||
Eastern Conference championship
| Quarter | 1 | 2 | 3 | 4 | Total |
|---|---|---|---|---|---|
| Browns | 0 | 0 | 0 | 0 | 0 |
| Giants | 7 | 3 | 0 | 0 | 10 |
at Yankee Stadium in The Bronx, New York City
- Date: December 21, 1958
- Game attendance: 61,274
| Game information |
|---|
First Quarter Second Quarter
Third Quarter
Fourth Quarter
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