Sexton, Iowa
Appearance
Sexton, Iowa | |
---|---|
Coordinates: 43°04′58″N 94°05′21″W / 43.08278°N 94.08917°W | |
Country | United States |
State | Iowa |
County | Kossuth |
Townships | Irvington, Prairie |
Post office opened | August 20, 1888 |
Area | |
• Total | 2.20 sq mi (5.70 km2) |
• Land | 2.20 sq mi (5.70 km2) |
• Water | 0 sq mi (0 km2) |
Elevation | 1,220 ft (370 m) |
Population | |
• Total | 37 |
• Density | 17/sq mi (6.5/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
ZIP Code | 50483 |
Area code | 515 |
GNIS feature ID | 461516[2] |
FIPS code | 19-71715 |
Sexton is an unincorporated community and census-designated place in Irvington Township, Kossuth County, Iowa, United States. It is located at the intersection of U.S. Route 18 and Kossuth CR P60. As of the 2010 census it had a population of 37.[1]
Sexton was platted in 1889.[3] The town contained a post office from August 1888 until May 1974.[4]
A few houses, a Racer's Bar and Grill and the Sexton elevator remain.
Geography
Sexton is in southeastern Kossuth County, 8 miles (13 km) east of Algona, the county seat, and 5 miles (8 km) west of Wesley. According to the U.S. Census Bureau, the Sexton CDP has an area of 2.2 square miles (5.7 km2), all land.[1] The CDP is on the south side of U.S. Route 18.
References
- ^ a b c d "Geographic Identifiers: 2010 Demographic Profile Data (G001): Sexton CDP, Iowa". American Factfinder. U.S. Census Bureau. Retrieved February 28, 2019.[dead link]
- ^ "Feature Detail Report for: Sexton." USGS. URL Retrieved June 26, 2010.
- ^ Reed, Benjamin F. (1913). History of Kossuth County, Iowa, Volume 1. S. J. Clarke Publishing Company. p. 589.
- ^ "Feature Detail Report for: Sexton Post Office (historical)." USGS. URL Retrieved June 26, 2010.