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1856 United States presidential election in Vermont

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1856 United States presidential election in Vermont

← 1852 November 4, 1856 1860 →
 
Nominee John C. Frémont James Buchanan
Party Republican Democratic
Home state California Pennsylvania
Running mate William L. Dayton John C. Breckinridge
Electoral vote 5 0
Popular vote 39,561 10,577
Percentage 77.96% 20.84%

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

The 1856 United States presidential election in Vermont took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the Republican candidate, John C. Frémont, over the Democratic candidate, James Buchanan, and the Know Nothing candidate, Millard Fillmore. Frémont won the state by a margin of 57.12%.

With 77.96% of the popular vote, Vermont would be his strongest victory in the Union in terms of percentage in the popular vote.[1]

Frémont's victory also started the long streak of Republican presidential candidate victories within the Green Mountain State, which wouldn't be broken until 108 years later in 1964.

Results

1856 United States presidential election in Vermont[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican John C. Frémont of California William L. Dayton of New Jersey 39,561 77.96% 5 100.00%
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 10,577 20.84% 0 0.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 545 1.07% 0 0.00%
N/A Others Others 65 0.13% 0 0.00%
Total 47,922 100.00% 5 100.00%

See also

References

  1. ^ "1856 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ "1856 Presidential General Election Results - Vermont".