Douglas Township, Saunders County, Nebraska
Douglas Township | |
|---|---|
 Location in Saunders County | |
| Coordinates: 41°21′06″N 096°44′13″W / 41.35167°N 96.73694°W | |
| Country | United States |
| State | Nebraska |
| County | Saunders |
| Area | |
• Total | 32.01 sq mi (82.91 km2) |
| • Land | 32.01 sq mi (82.91 km2) |
| • Water | 0 sq mi (0 km2) 0% |
| Elevation | 1,309 ft (399 m) |
| Population (2000) | |
• Total | 196 |
| • Density | 6.1/sq mi (2.4/km2) |
| GNIS feature ID | 0837967 |
Douglas Township is one of twenty-four townships in Saunders County, Nebraska, United States. The population was 196 at the 2000 census. A 2006 estimate placed the township's population at 205.[1]
See also
References
- ^ "Subcounty population estimates: Nebraska 2000-2006". United States Census Bureau, Population Division. 2007-06-28. Archived from the original (CSV) on 2008-02-18. Retrieved 2008-03-04.
External links
Municipalities and communities of Saunders County, Nebraska, United States | ||
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| Cities |  | |
| Villages | ||
| Townships | ||
| CDP | ||
| Unincorporated communities | ||
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