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1792 United States presidential election in Delaware

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1792 United States presidential election in Delaware

← 1789 November 2 – December 5, 1792 1796 →
 
Nominee George Washington John Adams
Party Nonpartisan Federalist
Home state Virginia Massachusetts
Electoral vote 3 3
Percentage 100%

President before election

George Washington
Nonpartisanism

Elected President

George Washington
Nonpartisanism

The 1792 United States presidential election in Delaware took place between November 2 and December 5, 1792 as part of the 1792 United States presidential election. The state legislature chose three members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Delaware's three electors each cast one vote for the incumbent, George Washington, and one vote for John Adams, the incumbent Vice President.[1]

Results

United States presidential election in Delaware, 1792
Party Candidate Votes Percentage Electoral votes
Nonpartisan George Washington 100.00% 3
Totals 100.00% 3

See also

References

  1. ^ 1792 Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.